In case the body have to stay in lower temperature for extended time period (more than 1 hour), how does the body regulate its response?

## In case the body have to stay in lower temperature for extended time period (more than 1 hour), how does the body regulate its response?

Arterioles transporting blood to external capillaries beneath the surface of … Read More...
A particular group of men have heights with a mean of 169169 cm and a standard deviation of 88 cm. JordanJordan had a height of 174174 cm. a.a. What is the positive difference between JordanJordan?’s height and the? mean? b.b. How many standard deviations is that? [the difference found in part? (a)]? c.c. Convert JordanJordan?’s height to a z score. d.d. If we consider? “usual” heights to be those that convert to z scores between minus-2 and? 2, is JordanJordan?’s height usual or? unusual?

## A particular group of men have heights with a mean of 169169 cm and a standard deviation of 88 cm. JordanJordan had a height of 174174 cm. a.a. What is the positive difference between JordanJordan?’s height and the? mean? b.b. How many standard deviations is that? [the difference found in part? (a)]? c.c. Convert JordanJordan?’s height to a z score. d.d. If we consider? “usual” heights to be those that convert to z scores between minus-2 and? 2, is JordanJordan?’s height usual or? unusual?

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The Geographic Grid The Geographic grid is based on angular measurements from the center of the earth. Latitude measures the angular distance north and south of the plane of the earth’s equator. longitude measures the angular distance east and west of the prime meridian. The angular distance between any two locations on the earth’s surface is simply the latitudinal or longitudinal difference the two locations. Both longitude and latitude are measured in degrees ( o ), minutes ( ‘ ) and seconds ( ” ) of arc. Figure 1 shows the latitude and longitude coordinates of the earth in 10o degree intervals. There are 60′ minutes of arc in 1o . There are 60″ seconds of arc in 1′ minute of arc. One could therefore express the latitude and longitude of a place as 39o 50′ 10″ N, 77o 35′ 15″ W. 1. Using latitude and longitude coordinates, determine the location of the following places. a) Toronto, Ontario ( Canada ) ____________________________________________________________ b) Billings, Montana _____________________________________________________________________ c) Chicago, Illinois ______________________________________________________________________ d) Westminster, England _________________________________________________________________ e) Venice, Italy _________________________________________________________________________ f) Baghdad, Iraq _______________________________________________________________________ g) Tokyo, Japan ________________________________________________________________________ h) Rio de Janeiro, Brazil _________________________________________________________________ 2. Provide the name of the following places located at the given coordinates below. a) 13o 09′ 50.19″ S, 72o 32′ 45.58″ W ______________________________________________________ b) 33o 51′ 35.90″ S, 151o 12′ 40″ E ______________________________________________________ c) 71o 17′ 07.62″ N, 156o 45′ 57.98″ W _____________________________________________________ d) 41o 53′ 29.84″ N, 87o 36′ 01.78″ W ______________________________________________________ The geographic grid uses circles of two different types, great circles and small circles. All great circles pass through the geographic center of the earth. All meridians, the equator, and the circle of illumination are great circles. All parallels other than the equator are small circles. The direction of any grid lines ( meridians and parallels ) can be determined as either an azimuth or a bearing. Azimuths are read in a clockwise direction as degrees ranging from 0o at the North Pole, to 90o at East, to 180o at the South Pole, to 270o at West, and back to 360o at the North Pole. Azimuths only give a direction such as 45o . Bearings are read as quadrants from either the North or South Poles. Hence east is 90o from either North or South. West is also 90o from either North or South. A bearing shows the direction one is traveling as well as the magnitude of the angle from either North or South. Hence a azimuth of 45o is read as a bearing of N 45o E. An azimuth of 150o would as a bearing read S 30o E. Figure 1.2 shows the relationship between azimuths and bearings. 3. Convert the values below. Bearing Azimuth 20o S 500 20′ E 265o 30’ N 20o 20 W Longitudinal and latitudinal distances vary as a result of trying to fit a flat grid onto a spherical surface such as the earth’s curved surface. The grid is constant in a north-south direction, but varies in the east-west direction. The data below shows how the grid values vary ( rounded off to the nearest mile of distance ). 1o of longitude at the equator = 69 miles 1o of longitude at the 30th parallel = 60 miles 1o of longitude at the 60th parallel = 35 miles 1o of longitude at the 90th parallel = 0 miles 1o of latitude along any meridian = 69 miles 4. Determine by calculation the linear ( miles ) and angular ( degree ) distances between the following places. From To Angular Linear Quito, Ecuador Macapa, Brazil 0o S, 78o W 0o N, 51o W Cairo, Egypt Shiraz, Iran 30o N, 31o E 30o N, 52o E Seward, Alaska St Petersburg, Russia 60o N, 149o W 60o N, 30o E Hamhung, North Korea Ankara, Turkey 39o N, 127o E 39o N, 32o E Detroit, Michigan Morristown, Tennessee 42o N, 83o W 36o N, 83o W Sample problem We see that between Quito and Macapa that there is no latitude difference as both places are at 0 degrees latitude. Therefore the angular difference between the two places can only be calculated based upon the longitudinal difference. Seeing that both places are west longitude we simply subtract 78-51 = 27 degrees. Hence the angular distance between Quito and Macapa is 27 degrees. The linear distance is the number of miles ( feet,yards, kilometers, etc.) Quito and Macapa. Bothe places are on the equator so consulting the table above we find that in 1 degree of longitude ate the equator is equal to 69 miles. So multiplying the 69 miles/degree X 27 degrees, the degrees cancel and the remaining units are miles, and the numerical value is 1,863 linear miles.

## The Geographic Grid The Geographic grid is based on angular measurements from the center of the earth. Latitude measures the angular distance north and south of the plane of the earth’s equator. longitude measures the angular distance east and west of the prime meridian. The angular distance between any two locations on the earth’s surface is simply the latitudinal or longitudinal difference the two locations. Both longitude and latitude are measured in degrees ( o ), minutes ( ‘ ) and seconds ( ” ) of arc. Figure 1 shows the latitude and longitude coordinates of the earth in 10o degree intervals. There are 60′ minutes of arc in 1o . There are 60″ seconds of arc in 1′ minute of arc. One could therefore express the latitude and longitude of a place as 39o 50′ 10″ N, 77o 35′ 15″ W. 1. Using latitude and longitude coordinates, determine the location of the following places. a) Toronto, Ontario ( Canada ) ____________________________________________________________ b) Billings, Montana _____________________________________________________________________ c) Chicago, Illinois ______________________________________________________________________ d) Westminster, England _________________________________________________________________ e) Venice, Italy _________________________________________________________________________ f) Baghdad, Iraq _______________________________________________________________________ g) Tokyo, Japan ________________________________________________________________________ h) Rio de Janeiro, Brazil _________________________________________________________________ 2. Provide the name of the following places located at the given coordinates below. a) 13o 09′ 50.19″ S, 72o 32′ 45.58″ W ______________________________________________________ b) 33o 51′ 35.90″ S, 151o 12′ 40″ E ______________________________________________________ c) 71o 17′ 07.62″ N, 156o 45′ 57.98″ W _____________________________________________________ d) 41o 53′ 29.84″ N, 87o 36′ 01.78″ W ______________________________________________________ The geographic grid uses circles of two different types, great circles and small circles. All great circles pass through the geographic center of the earth. All meridians, the equator, and the circle of illumination are great circles. All parallels other than the equator are small circles. The direction of any grid lines ( meridians and parallels ) can be determined as either an azimuth or a bearing. Azimuths are read in a clockwise direction as degrees ranging from 0o at the North Pole, to 90o at East, to 180o at the South Pole, to 270o at West, and back to 360o at the North Pole. Azimuths only give a direction such as 45o . Bearings are read as quadrants from either the North or South Poles. Hence east is 90o from either North or South. West is also 90o from either North or South. A bearing shows the direction one is traveling as well as the magnitude of the angle from either North or South. Hence a azimuth of 45o is read as a bearing of N 45o E. An azimuth of 150o would as a bearing read S 30o E. Figure 1.2 shows the relationship between azimuths and bearings. 3. Convert the values below. Bearing Azimuth 20o S 500 20′ E 265o 30’ N 20o 20 W Longitudinal and latitudinal distances vary as a result of trying to fit a flat grid onto a spherical surface such as the earth’s curved surface. The grid is constant in a north-south direction, but varies in the east-west direction. The data below shows how the grid values vary ( rounded off to the nearest mile of distance ). 1o of longitude at the equator = 69 miles 1o of longitude at the 30th parallel = 60 miles 1o of longitude at the 60th parallel = 35 miles 1o of longitude at the 90th parallel = 0 miles 1o of latitude along any meridian = 69 miles 4. Determine by calculation the linear ( miles ) and angular ( degree ) distances between the following places. From To Angular Linear Quito, Ecuador Macapa, Brazil 0o S, 78o W 0o N, 51o W Cairo, Egypt Shiraz, Iran 30o N, 31o E 30o N, 52o E Seward, Alaska St Petersburg, Russia 60o N, 149o W 60o N, 30o E Hamhung, North Korea Ankara, Turkey 39o N, 127o E 39o N, 32o E Detroit, Michigan Morristown, Tennessee 42o N, 83o W 36o N, 83o W Sample problem We see that between Quito and Macapa that there is no latitude difference as both places are at 0 degrees latitude. Therefore the angular difference between the two places can only be calculated based upon the longitudinal difference. Seeing that both places are west longitude we simply subtract 78-51 = 27 degrees. Hence the angular distance between Quito and Macapa is 27 degrees. The linear distance is the number of miles ( feet,yards, kilometers, etc.) Quito and Macapa. Bothe places are on the equator so consulting the table above we find that in 1 degree of longitude ate the equator is equal to 69 miles. So multiplying the 69 miles/degree X 27 degrees, the degrees cancel and the remaining units are miles, and the numerical value is 1,863 linear miles.

Standard based Curriculum In standard based curriculum, the initial point … Read More...